Base | Representation |
---|---|
bin | 10010100100000010001… |
… | …101010011010000000011 |
3 | 11111221122201002111212122 |
4 | 102210002031103100003 |
5 | 131400003413444232 |
6 | 2414004430114455 |
7 | 161106414611522 |
oct | 22440215232003 |
9 | 4457581074778 |
10 | 1275642328067 |
11 | 451aa6924808 |
12 | 18728a04ba2b |
13 | 933a5989c03 |
14 | 45a546464b9 |
15 | 232b0832312 |
hex | 12902353403 |
1275642328067 has 2 divisors, whose sum is σ = 1275642328068. Its totient is φ = 1275642328066.
The previous prime is 1275642328057. The next prime is 1275642328069. The reversal of 1275642328067 is 7608232465721.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1275642328067 - 214 = 1275642311683 is a prime.
Together with 1275642328069, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1275642328069) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 637821164033 + 637821164034.
It is an arithmetic number, because the mean of its divisors is an integer number (637821164034).
Almost surely, 21275642328067 is an apocalyptic number.
1275642328067 is a deficient number, since it is larger than the sum of its proper divisors (1).
1275642328067 is an equidigital number, since it uses as much as digits as its factorization.
1275642328067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6773760, while the sum is 53.
The spelling of 1275642328067 in words is "one trillion, two hundred seventy-five billion, six hundred forty-two million, three hundred twenty-eight thousand, sixty-seven".
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