Search a number
-
+
127977711413 is a prime number
BaseRepresentation
bin111011100110000010…
…0001110011100110101
3110020022222122100012112
41313030010032130311
54044044243231123
6134443034300405
712150256412156
oct1671404163465
9406288570175
10127977711413
114a303099852
1220977587705
13c0b6c25476
1462a0a8b92d
1534e054bd78
hex1dcc10e735

127977711413 has 2 divisors, whose sum is σ = 127977711414. Its totient is φ = 127977711412.

The previous prime is 127977711349. The next prime is 127977711419. The reversal of 127977711413 is 314117779721.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 127561836964 + 415874449 = 357158^2 + 20393^2 .

It is an emirp because it is prime and its reverse (314117779721) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 127977711413 - 26 = 127977711349 is a prime.

It is a super-2 number, since 2×1279777114132 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (127977711419) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63988855706 + 63988855707.

It is an arithmetic number, because the mean of its divisors is an integer number (63988855707).

Almost surely, 2127977711413 is an apocalyptic number.

It is an amenable number.

127977711413 is a deficient number, since it is larger than the sum of its proper divisors (1).

127977711413 is an equidigital number, since it uses as much as digits as its factorization.

127977711413 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 518616, while the sum is 50.

The spelling of 127977711413 in words is "one hundred twenty-seven billion, nine hundred seventy-seven million, seven hundred eleven thousand, four hundred thirteen".