Base | Representation |
---|---|
bin | 111011100111011110… |
… | …0110011110000111111 |
3 | 110020110100200200011011 |
4 | 1313032330303300333 |
5 | 4044144140130001 |
6 | 134451523340051 |
7 | 12151414612135 |
oct | 1671674636077 |
9 | 406410620134 |
10 | 128026098751 |
11 | 4a328438991 |
12 | 2098b821627 |
13 | c0c3c67825 |
14 | 62a7285755 |
15 | 34e4908d51 |
hex | 1dcef33c3f |
128026098751 has 2 divisors, whose sum is σ = 128026098752. Its totient is φ = 128026098750.
The previous prime is 128026098703. The next prime is 128026098763. The reversal of 128026098751 is 157890620821.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 128026098751 - 215 = 128026065983 is a prime.
It is a super-2 number, since 2×1280260987512 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 128026098695 and 128026098704.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (128026098701) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 64013049375 + 64013049376.
It is an arithmetic number, because the mean of its divisors is an integer number (64013049376).
Almost surely, 2128026098751 is an apocalyptic number.
128026098751 is a deficient number, since it is larger than the sum of its proper divisors (1).
128026098751 is an equidigital number, since it uses as much as digits as its factorization.
128026098751 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 483840, while the sum is 49.
The spelling of 128026098751 in words is "one hundred twenty-eight billion, twenty-six million, ninety-eight thousand, seven hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.083 sec. • engine limits •