Base | Representation |
---|---|
bin | 1011101001010111101011… |
… | …0111000001011011011111 |
3 | 1200100011212110122201122001 |
4 | 2322111322313001123133 |
5 | 3134300333320103003 |
6 | 43122411155103131 |
7 | 2461104504324421 |
oct | 272257267013337 |
9 | 50304773581561 |
10 | 12805358753503 |
11 | 40977a41aa3a8 |
12 | 15299208a1aa7 |
13 | 71b703927404 |
14 | 323ad5910811 |
15 | 17316b8d161d |
hex | ba57adc16df |
12805358753503 has 2 divisors, whose sum is σ = 12805358753504. Its totient is φ = 12805358753502.
The previous prime is 12805358753501. The next prime is 12805358753599. The reversal of 12805358753503 is 30535785350821.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12805358753503 - 21 = 12805358753501 is a prime.
Together with 12805358753501, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12805358753501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6402679376751 + 6402679376752.
It is an arithmetic number, because the mean of its divisors is an integer number (6402679376752).
Almost surely, 212805358753503 is an apocalyptic number.
12805358753503 is a deficient number, since it is larger than the sum of its proper divisors (1).
12805358753503 is an equidigital number, since it uses as much as digits as its factorization.
12805358753503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15120000, while the sum is 55.
The spelling of 12805358753503 in words is "twelve trillion, eight hundred five billion, three hundred fifty-eight million, seven hundred fifty-three thousand, five hundred three".
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