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12808632343601 is a prime number
BaseRepresentation
bin1011101001100011110111…
…1110110001110000110001
31200100111022121111100000202
42322120331332301300301
53134324034334443401
643124112055324545
72461251564353033
oct272307576616061
950314277440022
1012808632343601
114099124046066
12152a495080755
1371bb05bc0883
14323d265b3c53
151732adeb906b
hexba63dfb1c31

12808632343601 has 2 divisors, whose sum is σ = 12808632343602. Its totient is φ = 12808632343600.

The previous prime is 12808632343553. The next prime is 12808632343603. The reversal of 12808632343601 is 10634323680821.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8910219030001 + 3898413313600 = 2984999^2 + 1974440^2 .

It is a cyclic number.

It is not a de Polignac number, because 12808632343601 - 26 = 12808632343537 is a prime.

It is a super-2 number, since 2×128086323436012 (a number of 27 digits) contains 22 as substring.

Together with 12808632343603, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12808632343603) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6404316171800 + 6404316171801.

It is an arithmetic number, because the mean of its divisors is an integer number (6404316171801).

Almost surely, 212808632343601 is an apocalyptic number.

It is an amenable number.

12808632343601 is a deficient number, since it is larger than the sum of its proper divisors (1).

12808632343601 is an equidigital number, since it uses as much as digits as its factorization.

12808632343601 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 995328, while the sum is 47.

The spelling of 12808632343601 in words is "twelve trillion, eight hundred eight billion, six hundred thirty-two million, three hundred forty-three thousand, six hundred one".