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128120214301 is a prime number
BaseRepresentation
bin111011101010010001…
…1110101001100011101
3110020200220210020102021
41313110203311030131
54044342233324201
6134505124500141
712153636565402
oct1672443651435
9406626706367
10128120214301
114a376580332
12209b724a651
13c10a5caac1
1462b59842a9
1534ecce9ea1
hex1dd48f531d

128120214301 has 2 divisors, whose sum is σ = 128120214302. Its totient is φ = 128120214300.

The previous prime is 128120214283. The next prime is 128120214311. The reversal of 128120214301 is 103412021821.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 126017900100 + 2102314201 = 354990^2 + 45851^2 .

It is an emirp because it is prime and its reverse (103412021821) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 128120214301 - 29 = 128120213789 is a prime.

It is a super-3 number, since 3×1281202143013 (a number of 34 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (128120214311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 64060107150 + 64060107151.

It is an arithmetic number, because the mean of its divisors is an integer number (64060107151).

Almost surely, 2128120214301 is an apocalyptic number.

It is an amenable number.

128120214301 is a deficient number, since it is larger than the sum of its proper divisors (1).

128120214301 is an equidigital number, since it uses as much as digits as its factorization.

128120214301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 25.

The spelling of 128120214301 in words is "one hundred twenty-eight billion, one hundred twenty million, two hundred fourteen thousand, three hundred one".