Base | Representation |
---|---|
bin | 10010101001011101000… |
… | …000100011011111101011 |
3 | 11112111200012100110011222 |
4 | 102221131000203133223 |
5 | 131443412413240213 |
6 | 2420410033412255 |
7 | 161403535030631 |
oct | 22513500433753 |
9 | 4474605313158 |
10 | 1281460680683 |
11 | 454512168197 |
12 | 18843270a08b |
13 | 93ac2226001 |
14 | 4604728d351 |
15 | 23501538808 |
hex | 12a5d0237eb |
1281460680683 has 2 divisors, whose sum is σ = 1281460680684. Its totient is φ = 1281460680682.
The previous prime is 1281460680631. The next prime is 1281460680719. The reversal of 1281460680683 is 3860860641821.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (3860860641821) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1281460680683 - 216 = 1281460615147 is a prime.
It is a super-2 number, since 2×12814606806832 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1281460686683) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 640730340341 + 640730340342.
It is an arithmetic number, because the mean of its divisors is an integer number (640730340342).
Almost surely, 21281460680683 is an apocalyptic number.
1281460680683 is a deficient number, since it is larger than the sum of its proper divisors (1).
1281460680683 is an equidigital number, since it uses as much as digits as its factorization.
1281460680683 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2654208, while the sum is 53.
The spelling of 1281460680683 in words is "one trillion, two hundred eighty-one billion, four hundred sixty million, six hundred eighty thousand, six hundred eighty-three".
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