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1281481193173 is a prime number
BaseRepresentation
bin10010101001011110001…
…110110011011011010101
311112111201121221121000211
4102221132032303123111
5131443433141140143
62420412045205421
7161404204263046
oct22513616633325
94474647847024
101281481193173
114545227a8565
12188439560871
1393ac655878c
1446049cac8cd
152350323b49d
hex12a5e3b36d5

1281481193173 has 2 divisors, whose sum is σ = 1281481193174. Its totient is φ = 1281481193172.

The previous prime is 1281481193129. The next prime is 1281481193177. The reversal of 1281481193173 is 3713911841821.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 951157424529 + 330323768644 = 975273^2 + 574738^2 .

It is an emirp because it is prime and its reverse (3713911841821) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1281481193173 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1281481193177) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 640740596586 + 640740596587.

It is an arithmetic number, because the mean of its divisors is an integer number (640740596587).

Almost surely, 21281481193173 is an apocalyptic number.

It is an amenable number.

1281481193173 is a deficient number, since it is larger than the sum of its proper divisors (1).

1281481193173 is an equidigital number, since it uses as much as digits as its factorization.

1281481193173 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 290304, while the sum is 49.

The spelling of 1281481193173 in words is "one trillion, two hundred eighty-one billion, four hundred eighty-one million, one hundred ninety-three thousand, one hundred seventy-three".