12816614800907 has 2 divisors, whose sum is σ = 12816614800908. Its totient is φ = 12816614800906.

The previous prime is 12816614800897. The next prime is 12816614800909. The reversal of 12816614800907 is 70900841661821.

12816614800907 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12816614800907 is a prime.

It is a super-2 number, since 2×12816614800907² (a number of 27 digits) contains 22 as substring.

Together with 12816614800909, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12816614800909) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6408307400453 + 6408307400454.

It is an arithmetic number, because the mean of its divisors is an integer number (6408307400454).

Almost surely, 2^{12816614800907} is an apocalyptic number.

12816614800907 is a deficient number, since it is larger than the sum of its proper divisors (1).

12816614800907 is an equidigital number, since it uses as much as digits as its factorization.

12816614800907 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1161216, while the sum is 53.

The spelling of 12816614800907 in words is "twelve trillion, eight hundred sixteen billion, six hundred fourteen million, eight hundred thousand, nine hundred seven".