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12825482413 is a prime number
BaseRepresentation
bin10111111000111010…
…10101010010101101
31020002211102000100011
423330131111102231
5202231310414123
65520354333221
7632553542002
oct137435252255
936084360304
1012825482413
115491717847
12259b28a211
13129519a363
148994db8a9
15500e7ce0d
hex2fc7554ad

12825482413 has 2 divisors, whose sum is σ = 12825482414. Its totient is φ = 12825482412.

The previous prime is 12825482407. The next prime is 12825482497. The reversal of 12825482413 is 31428452821.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12241873449 + 583608964 = 110643^2 + 24158^2 .

It is an emirp because it is prime and its reverse (31428452821) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12825482413 - 25 = 12825482381 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12825482113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6412741206 + 6412741207.

It is an arithmetic number, because the mean of its divisors is an integer number (6412741207).

Almost surely, 212825482413 is an apocalyptic number.

It is an amenable number.

12825482413 is a deficient number, since it is larger than the sum of its proper divisors (1).

12825482413 is an equidigital number, since it uses as much as digits as its factorization.

12825482413 is an evil number, because the sum of its binary digits is even.

The product of its digits is 122880, while the sum is 40.

The spelling of 12825482413 in words is "twelve billion, eight hundred twenty-five million, four hundred eighty-two thousand, four hundred thirteen".