Search a number
-
+
1283194304981 is a prime number
BaseRepresentation
bin10010101011000100010…
…101110011100111010101
311112200011000110200122022
4102223010111303213111
5132010440220224411
62421254043142525
7161464515425111
oct22530425634725
94480130420568
101283194304981
11455221806846
12188837214a45
139400a4460c4
144616d608741
15235a382eedb
hex12ac45739d5

1283194304981 has 2 divisors, whose sum is σ = 1283194304982. Its totient is φ = 1283194304980.

The previous prime is 1283194304969. The next prime is 1283194305013. The reversal of 1283194304981 is 1894034913821.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 745098702481 + 538095602500 = 863191^2 + 733550^2 .

It is an emirp because it is prime and its reverse (1894034913821) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1283194304981 - 222 = 1283190110677 is a prime.

It is a super-2 number, since 2×12831943049812 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1283194304681) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 641597152490 + 641597152491.

It is an arithmetic number, because the mean of its divisors is an integer number (641597152491).

Almost surely, 21283194304981 is an apocalyptic number.

It is an amenable number.

1283194304981 is a deficient number, since it is larger than the sum of its proper divisors (1).

1283194304981 is an equidigital number, since it uses as much as digits as its factorization.

1283194304981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1492992, while the sum is 53.

The spelling of 1283194304981 in words is "one trillion, two hundred eighty-three billion, one hundred ninety-four million, three hundred four thousand, nine hundred eighty-one".