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128333382555407 is a prime number
BaseRepresentation
bin11101001011011111110001…
…101011100001011100001111
3121211101112220002020222121212
4131023133301223201130033
5113310103231413233112
61132535313030045035
736013531566155351
oct3513376153413417
9554345802228555
10128333382555407
1137988977898707
1212487a521a977b
13567ba2ac403a3
1423995242050d1
15ec83a4812522
hex74b7f1ae170f

128333382555407 has 2 divisors, whose sum is σ = 128333382555408. Its totient is φ = 128333382555406.

The previous prime is 128333382555283. The next prime is 128333382555481. The reversal of 128333382555407 is 704555283333821.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 128333382555407 - 214 = 128333382539023 is a prime.

It is a super-2 number, since 2×1283333825554072 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (128333382555107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 64166691277703 + 64166691277704.

It is an arithmetic number, because the mean of its divisors is an integer number (64166691277704).

Almost surely, 2128333382555407 is an apocalyptic number.

128333382555407 is a deficient number, since it is larger than the sum of its proper divisors (1).

128333382555407 is an equidigital number, since it uses as much as digits as its factorization.

128333382555407 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72576000, while the sum is 59.

The spelling of 128333382555407 in words is "one hundred twenty-eight trillion, three hundred thirty-three billion, three hundred eighty-two million, five hundred fifty-five thousand, four hundred seven".