Base | Representation |
---|---|
bin | 1011101011011001001100… |
… | …0110010000100000111111 |
3 | 1200110111121101202002201121 |
4 | 2322312103012100200333 |
5 | 3140333034013422012 |
6 | 43150401055251411 |
7 | 2463445161612055 |
oct | 272662306204077 |
9 | 50414541662647 |
10 | 12840125139007 |
11 | 4100514999401 |
12 | 1534603b19b67 |
13 | 721a8462485a |
14 | 325672da81d5 |
15 | 174003bb7a07 |
hex | bad9319083f |
12840125139007 has 2 divisors, whose sum is σ = 12840125139008. Its totient is φ = 12840125139006.
The previous prime is 12840125139001. The next prime is 12840125139053. The reversal of 12840125139007 is 70093152104821.
12840125139007 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (70093152104821) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12840125139007 - 219 = 12840124614719 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12840125139001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6420062569503 + 6420062569504.
It is an arithmetic number, because the mean of its divisors is an integer number (6420062569504).
Almost surely, 212840125139007 is an apocalyptic number.
12840125139007 is a deficient number, since it is larger than the sum of its proper divisors (1).
12840125139007 is an equidigital number, since it uses as much as digits as its factorization.
12840125139007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120960, while the sum is 43.
The spelling of 12840125139007 in words is "twelve trillion, eight hundred forty billion, one hundred twenty-five million, one hundred thirty-nine thousand, seven".
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