12840125139053 has 2 divisors, whose sum is σ = 12840125139054. Its totient is φ = 12840125139052.

The previous prime is 12840125139007. The next prime is 12840125139071. The reversal of 12840125139053 is 35093152104821.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12302429980324 + 537695158729 = 3507482^2 + 733277^2 .

It is a cyclic number.

It is not a de Polignac number, because 12840125139053 - 2⁶ = 12840125138989 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12840125138995 and 12840125139013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12840125139353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6420062569526 + 6420062569527.

It is an arithmetic number, because the mean of its divisors is an integer number (6420062569527).

Almost surely, 2^{12840125139053} is an apocalyptic number.

It is an amenable number.

12840125139053 is a deficient number, since it is larger than the sum of its proper divisors (1).

12840125139053 is an equidigital number, since it uses as much as digits as its factorization.

12840125139053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 259200, while the sum is 44.

The spelling of 12840125139053 in words is "twelve trillion, eight hundred forty billion, one hundred twenty-five million, one hundred thirty-nine thousand, fifty-three".