Base | Representation |
---|---|
bin | 111011110101000111… |
… | …0101110010000110111 |
3 | 110021122020220021022011 |
4 | 1313222032232100313 |
5 | 4101113321422024 |
6 | 135005153145051 |
7 | 12165643051555 |
oct | 1675216562067 |
9 | 407566807264 |
10 | 128483779639 |
11 | 4a542820356 |
12 | 20a98b5b187 |
13 | c167a23617 |
14 | 630bd82bd5 |
15 | 351ebb3094 |
hex | 1dea3ae437 |
128483779639 has 2 divisors, whose sum is σ = 128483779640. Its totient is φ = 128483779638.
The previous prime is 128483779637. The next prime is 128483779649. The reversal of 128483779639 is 936977384821.
It is a weak prime.
It is an emirp because it is prime and its reverse (936977384821) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 128483779639 - 21 = 128483779637 is a prime.
It is a super-2 number, since 2×1284837796392 (a number of 23 digits) contains 22 as substring.
Together with 128483779637, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (128483779637) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 64241889819 + 64241889820.
It is an arithmetic number, because the mean of its divisors is an integer number (64241889820).
Almost surely, 2128483779639 is an apocalyptic number.
128483779639 is a deficient number, since it is larger than the sum of its proper divisors (1).
128483779639 is an equidigital number, since it uses as much as digits as its factorization.
128483779639 is an evil number, because the sum of its binary digits is even.
The product of its digits is 109734912, while the sum is 67.
The spelling of 128483779639 in words is "one hundred twenty-eight billion, four hundred eighty-three million, seven hundred seventy-nine thousand, six hundred thirty-nine".
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