Base | Representation |
---|---|
bin | 10010101100101010111… |
… | …110100010111111110011 |
3 | 11112211121000122010000122 |
4 | 102230222332202333303 |
5 | 132023002030321401 |
6 | 2422140554440455 |
7 | 161555265003446 |
oct | 22545276427763 |
9 | 4484530563018 |
10 | 1284916260851 |
11 | 455a25805773 |
12 | 189037a3312b |
13 | 9422310c0c2 |
14 | 462941a765d |
15 | 23654abe21b |
hex | 12b2afa2ff3 |
1284916260851 has 2 divisors, whose sum is σ = 1284916260852. Its totient is φ = 1284916260850.
The previous prime is 1284916260841. The next prime is 1284916260853. The reversal of 1284916260851 is 1580626194821.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1284916260851 - 234 = 1267736391667 is a prime.
Together with 1284916260853, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 1284916260793 and 1284916260802.
It is not a weakly prime, because it can be changed into another prime (1284916260853) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 642458130425 + 642458130426.
It is an arithmetic number, because the mean of its divisors is an integer number (642458130426).
Almost surely, 21284916260851 is an apocalyptic number.
1284916260851 is a deficient number, since it is larger than the sum of its proper divisors (1).
1284916260851 is an equidigital number, since it uses as much as digits as its factorization.
1284916260851 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1658880, while the sum is 53.
The spelling of 1284916260851 in words is "one trillion, two hundred eighty-four billion, nine hundred sixteen million, two hundred sixty thousand, eight hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •