Base | Representation |
---|---|
bin | 1011101110100100000000… |
… | …0110010000111000011111 |
3 | 1200122201010120002200022011 |
4 | 2323221000012100320133 |
5 | 3142231033201101211 |
6 | 43231403221532051 |
7 | 2500413252551521 |
oct | 273510006207037 |
9 | 50581116080264 |
10 | 12894567206431 |
11 | 4121612033459 |
12 | 1543078574027 |
13 | 726c4c766131 |
14 | 328159643a11 |
15 | 17563d505921 |
hex | bba40190e1f |
12894567206431 has 2 divisors, whose sum is σ = 12894567206432. Its totient is φ = 12894567206430.
The previous prime is 12894567206399. The next prime is 12894567206441. The reversal of 12894567206431 is 13460276549821.
It is a strong prime.
It is an emirp because it is prime and its reverse (13460276549821) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12894567206431 - 25 = 12894567206399 is a prime.
It is a super-2 number, since 2×128945672064312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12894567206441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6447283603215 + 6447283603216.
It is an arithmetic number, because the mean of its divisors is an integer number (6447283603216).
It is a 1-persistent number, because it is pandigital, but 2⋅12894567206431 = 25789134412862 is not.
Almost surely, 212894567206431 is an apocalyptic number.
12894567206431 is a deficient number, since it is larger than the sum of its proper divisors (1).
12894567206431 is an equidigital number, since it uses as much as digits as its factorization.
12894567206431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17418240, while the sum is 58.
The spelling of 12894567206431 in words is "twelve trillion, eight hundred ninety-four billion, five hundred sixty-seven million, two hundred six thousand, four hundred thirty-one".
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