13460276549821 has 2 divisors, whose sum is σ = 13460276549822. Its totient is φ = 13460276549820.

The previous prime is 13460276549813. The next prime is 13460276549879. The reversal of 13460276549821 is 12894567206431.

It is an a-pointer prime, because the next prime (13460276549879) can be obtained adding 13460276549821 to its sum of digits (58).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11474065500921 + 1986211048900 = 3387339^2 + 1409330^2 .

It is an emirp because it is prime and its reverse (12894567206431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13460276549821 - 2³ = 13460276549813 is a prime.

It is a super-2 number, since 2×13460276549821² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13460276549921) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6730138274910 + 6730138274911.

It is an arithmetic number, because the mean of its divisors is an integer number (6730138274911).

It is a 1-persistent number, because it is pandigital, but 2⋅13460276549821 = 26920553099642 is not.

Almost surely, 2^{13460276549821} is an apocalyptic number.

It is an amenable number.

13460276549821 is a deficient number, since it is larger than the sum of its proper divisors (1).

13460276549821 is an equidigital number, since it uses as much as digits as its factorization.

13460276549821 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17418240, while the sum is 58.

The spelling of 13460276549821 in words is "thirteen trillion, four hundred sixty billion, two hundred seventy-six million, five hundred forty-nine thousand, eight hundred twenty-one".