Search a number
-
+
129148403 is a prime number
BaseRepresentation
bin1111011001010…
…10010111110011
3100000000102022012
413230222113303
5231030222103
620452033135
73125512646
oct754522763
9300012265
10129148403
11669a011a
12373027ab
13209aac97
141321ba5d
15b5112d8
hex7b2a5f3

129148403 has 2 divisors, whose sum is σ = 129148404. Its totient is φ = 129148402.

The previous prime is 129148399. The next prime is 129148417. The reversal of 129148403 is 304841921.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 129148403 - 22 = 129148399 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 129148403.

It is not a weakly prime, because it can be changed into another prime (129148423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 64574201 + 64574202.

It is an arithmetic number, because the mean of its divisors is an integer number (64574202).

Almost surely, 2129148403 is an apocalyptic number.

129148403 is a deficient number, since it is larger than the sum of its proper divisors (1).

129148403 is an equidigital number, since it uses as much as digits as its factorization.

129148403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 32.

The square root of 129148403 is about 11364.3478915422. The cubic root of 129148403 is about 505.4711193490.

It can be divided in two parts, 1291 and 48403, that added together give a palindrome (49694).

The spelling of 129148403 in words is "one hundred twenty-nine million, one hundred forty-eight thousand, four hundred three".