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12926425996117 is a prime number
BaseRepresentation
bin1011110000011010101100…
…0001111001101101010101
31200202202100212000212202201
42330012223001321231111
53143241310023333432
643254152414204501
72502621613031344
oct274065301715525
950682325025681
1012926425996117
114134080535707
121549289ab3731
13729c58c6338a
143298dc8a9b5b
151763a53ebee7
hexbc1ab079b55

12926425996117 has 2 divisors, whose sum is σ = 12926425996118. Its totient is φ = 12926425996116.

The previous prime is 12926425996019. The next prime is 12926425996129. The reversal of 12926425996117 is 71169952462921.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12106231318801 + 820194677316 = 3479401^2 + 905646^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12926425996117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12926425996817) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6463212998058 + 6463212998059.

It is an arithmetic number, because the mean of its divisors is an integer number (6463212998059).

Almost surely, 212926425996117 is an apocalyptic number.

It is an amenable number.

12926425996117 is a deficient number, since it is larger than the sum of its proper divisors (1).

12926425996117 is an equidigital number, since it uses as much as digits as its factorization.

12926425996117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 29393280, while the sum is 64.

The spelling of 12926425996117 in words is "twelve trillion, nine hundred twenty-six billion, four hundred twenty-five million, nine hundred ninety-six thousand, one hundred seventeen".