Base | Representation |
---|---|
bin | 11000000110011011… |
… | …10100011111010111 |
3 | 1020101201202000012222 |
4 | 30003031310133113 |
5 | 202444321401112 |
6 | 5535524332555 |
7 | 635431315301 |
oct | 140315643727 |
9 | 36351660188 |
10 | 12938856407 |
11 | 553a713364 |
12 | 261124415b |
13 | 12b2814369 |
14 | 8aa5b0971 |
15 | 50adc5372 |
hex | 3033747d7 |
12938856407 has 2 divisors, whose sum is σ = 12938856408. Its totient is φ = 12938856406.
The previous prime is 12938856373. The next prime is 12938856419. The reversal of 12938856407 is 70465883921.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12938856407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12938856467) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6469428203 + 6469428204.
It is an arithmetic number, because the mean of its divisors is an integer number (6469428204).
It is a 1-persistent number, because it is pandigital, but 2⋅12938856407 = 25877712814 is not.
Almost surely, 212938856407 is an apocalyptic number.
12938856407 is a deficient number, since it is larger than the sum of its proper divisors (1).
12938856407 is an equidigital number, since it uses as much as digits as its factorization.
12938856407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2903040, while the sum is 53.
The spelling of 12938856407 in words is "twelve billion, nine hundred thirty-eight million, eight hundred fifty-six thousand, four hundred seven".
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