12976814270471 has 2 divisors, whose sum is σ = 12976814270472. Its totient is φ = 12976814270470.

The previous prime is 12976814270411. The next prime is 12976814270473. The reversal of 12976814270471 is 17407241867921.

It is a strong prime.

It is an emirp because it is prime and its reverse (17407241867921) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12976814270471 - 2²⁶ = 12976747161607 is a prime.

It is a super-3 number, since 3×12976814270471³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 12976814270473, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12976814270471.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12976814270473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6488407135235 + 6488407135236.

It is an arithmetic number, because the mean of its divisors is an integer number (6488407135236).

Almost surely, 2^{12976814270471} is an apocalyptic number.

12976814270471 is a deficient number, since it is larger than the sum of its proper divisors (1).

12976814270471 is an equidigital number, since it uses as much as digits as its factorization.

12976814270471 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9483264, while the sum is 59.

The spelling of 12976814270471 in words is "twelve trillion, nine hundred seventy-six billion, eight hundred fourteen million, two hundred seventy thousand, four hundred seventy-one".