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1298001818681 is a prime number
BaseRepresentation
bin10010111000110110111…
…011111111010000111001
311121002100222102022202122
4102320312323333100321
5132231301431144211
62432143243411025
7162530460263021
oct22706673772071
94532328368678
101298001818681
11460530207a77
1218b68a223a75
139552a138b29
1446b76044a81
1523b6d7c16db
hex12e36eff439

1298001818681 has 2 divisors, whose sum is σ = 1298001818682. Its totient is φ = 1298001818680.

The previous prime is 1298001818623. The next prime is 1298001818683. The reversal of 1298001818681 is 1868181008921.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 815336761600 + 482665057081 = 902960^2 + 694741^2 .

It is a cyclic number.

It is not a de Polignac number, because 1298001818681 - 214 = 1298001802297 is a prime.

It is a super-2 number, since 2×12980018186812 (a number of 25 digits) contains 22 as substring.

Together with 1298001818683, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1298001818683) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 649000909340 + 649000909341.

It is an arithmetic number, because the mean of its divisors is an integer number (649000909341).

Almost surely, 21298001818681 is an apocalyptic number.

It is an amenable number.

1298001818681 is a deficient number, since it is larger than the sum of its proper divisors (1).

1298001818681 is an equidigital number, since it uses as much as digits as its factorization.

1298001818681 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 442368, while the sum is 53.

The spelling of 1298001818681 in words is "one trillion, two hundred ninety-eight billion, one million, eight hundred eighteen thousand, six hundred eighty-one".