Base | Representation |
---|---|
bin | 11000001101101110… |
… | …00111010010110101 |
3 | 1020112222211002021021 |
4 | 30012313013102311 |
5 | 203111000403411 |
6 | 5545551221141 |
7 | 640103200324 |
oct | 140667072265 |
9 | 36488732237 |
10 | 13000012981 |
11 | 557119418a |
12 | 26298177b1 |
13 | 12c23a7897 |
14 | 8b47700bb |
15 | 511455a71 |
hex | 306dc74b5 |
13000012981 has 2 divisors, whose sum is σ = 13000012982. Its totient is φ = 13000012980.
The previous prime is 13000012943. The next prime is 13000013021. The reversal of 13000012981 is 18921000031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12445410481 + 554602500 = 111559^2 + 23550^2 .
It is an emirp because it is prime and its reverse (18921000031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13000012981 - 27 = 13000012853 is a prime.
It is a super-2 number, since 2×130000129812 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13000012901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500006490 + 6500006491.
It is an arithmetic number, because the mean of its divisors is an integer number (6500006491).
Almost surely, 213000012981 is an apocalyptic number.
It is an amenable number.
13000012981 is a deficient number, since it is larger than the sum of its proper divisors (1).
13000012981 is an equidigital number, since it uses as much as digits as its factorization.
13000012981 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 25.
The spelling of 13000012981 in words is "thirteen billion, twelve thousand, nine hundred eighty-one".
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