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1300003151 is a prime number
BaseRepresentation
bin100110101111100…
…0111100101001111
310100121012000001212
41031133013211033
510130300100101
6332555325035
744133562436
oct11537074517
93317160055
101300003151
116078aa677
1230345077b
13179439545
14c492211d
15791e11bb
hex4d7c794f

1300003151 has 2 divisors, whose sum is σ = 1300003152. Its totient is φ = 1300003150.

The previous prime is 1300003139. The next prime is 1300003163. The reversal of 1300003151 is 1513000031.

It is a balanced prime because it is at equal distance from previous prime (1300003139) and next prime (1300003163).

It is an emirp because it is prime and its reverse (1513000031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1300003151 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1300003751) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650001575 + 650001576.

It is an arithmetic number, because the mean of its divisors is an integer number (650001576).

Almost surely, 21300003151 is an apocalyptic number.

1300003151 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300003151 is an equidigital number, since it uses as much as digits as its factorization.

1300003151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 45, while the sum is 14.

The square root of 1300003151 is about 36055.5564511214. The cubic root of 1300003151 is about 1091.3937648499.

Adding to 1300003151 its reverse (1513000031), we get a palindrome (2813003182).

The spelling of 1300003151 in words is "one billion, three hundred million, three thousand, one hundred fifty-one".