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13000101860257 is a prime number
BaseRepresentation
bin1011110100101101001001…
…1101000001001110100001
31201000210112110011120021121
42331023102131001032201
53200443202034012012
643352055255452241
72511140433402151
oct275132235011641
951023473146247
1013000101860257
114162348651926
12155b60b987081
13733b9ab00865
1432d2cb77c761
151782685a7a07
hexbd2d27413a1

13000101860257 has 2 divisors, whose sum is σ = 13000101860258. Its totient is φ = 13000101860256.

The previous prime is 13000101860219. The next prime is 13000101860293. The reversal of 13000101860257 is 75206810100031.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12998108773521 + 1993086736 = 3605289^2 + 44644^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13000101860257 is a prime.

It is a super-2 number, since 2×130001018602572 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13000101060257) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500050930128 + 6500050930129.

It is an arithmetic number, because the mean of its divisors is an integer number (6500050930129).

Almost surely, 213000101860257 is an apocalyptic number.

It is an amenable number.

13000101860257 is a deficient number, since it is larger than the sum of its proper divisors (1).

13000101860257 is an equidigital number, since it uses as much as digits as its factorization.

13000101860257 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10080, while the sum is 34.

Adding to 13000101860257 its reverse (75206810100031), we get a palindrome (88206911960288).

The spelling of 13000101860257 in words is "thirteen trillion, one hundred one million, eight hundred sixty thousand, two hundred fifty-seven".