Base | Representation |
---|---|
bin | 1011110100101101001010… |
… | …0001101111111001100111 |
3 | 1201000210112112111112220021 |
4 | 2331023102201233321213 |
5 | 3200443202343200012 |
6 | 43352055342220011 |
7 | 2511140450054452 |
oct | 275132241577147 |
9 | 51023475445807 |
10 | 13000103100007 |
11 | 4162349319311 |
12 | 155b610284607 |
13 | 733b9b145c3a |
14 | 32d2cb9c2499 |
15 | 178268750007 |
hex | bd2d286fe67 |
13000103100007 has 2 divisors, whose sum is σ = 13000103100008. Its totient is φ = 13000103100006.
The previous prime is 13000103099993. The next prime is 13000103100029. The reversal of 13000103100007 is 70000130100031.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13000103100007 - 215 = 13000103067239 is a prime.
It is a super-2 number, since 2×130001031000072 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13000103100067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500051550003 + 6500051550004.
It is an arithmetic number, because the mean of its divisors is an integer number (6500051550004).
Almost surely, 213000103100007 is an apocalyptic number.
13000103100007 is a deficient number, since it is larger than the sum of its proper divisors (1).
13000103100007 is an equidigital number, since it uses as much as digits as its factorization.
13000103100007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 63, while the sum is 16.
Adding to 13000103100007 its reverse (70000130100031), we get a palindrome (83000233200038).
The spelling of 13000103100007 in words is "thirteen trillion, one hundred three million, one hundred thousand, seven".
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