1300011110081 has 2 divisors, whose sum is σ = 1300011110082. Its totient is φ = 1300011110080.

The previous prime is 1300011110033. The next prime is 1300011110093. The reversal of 1300011110081 is 1800111100031.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1212110719681 + 87900390400 = 1100959^2 + 296480^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300011110081 - 2¹⁴ = 1300011093697 is a prime.

It is a super-2 number, since 2×1300011110081² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1300011110381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650005555040 + 650005555041.

It is an arithmetic number, because the mean of its divisors is an integer number (650005555041).

Almost surely, 2^{1300011110081} is an apocalyptic number.

It is an amenable number.

1300011110081 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300011110081 is an equidigital number, since it uses as much as digits as its factorization.

1300011110081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 17.

The spelling of 1300011110081 in words is "one trillion, three hundred billion, eleven million, one hundred ten thousand, eighty-one".