Base | Representation |
---|---|
bin | 1111011111110… |
… | …10100011100000 |
3 | 100001121202000022 |
4 | 13233322203200 |
5 | 231240013440 |
6 | 20522213012 |
7 | 3135664004 |
oct | 757724340 |
9 | 301552008 |
10 | 130001120 |
11 | 67422847 |
12 | 37654168 |
13 | 20c19152 |
14 | 133a0704 |
15 | b62dcb5 |
hex | 7bfa8e0 |
130001120 has 48 divisors (see below), whose sum is σ = 308166768. Its totient is φ = 51824640.
The previous prime is 130001117. The next prime is 130001149. The reversal of 130001120 is 21100031.
It is a Harshad number since it is a multiple of its sum of digits (8).
It is a junction number, because it is equal to n+sod(n) for n = 130001098 and 130001107.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 52715 + ... + 55125.
It is an arithmetic number, because the mean of its divisors is an integer number (6420141).
Almost surely, 2130001120 is an apocalyptic number.
130001120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 130001120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (154083384).
130001120 is an abundant number, since it is smaller than the sum of its proper divisors (178165648).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130001120 is a wasteful number, since it uses less digits than its factorization.
130001120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2763 (or 2755 counting only the distinct ones).
The product of its (nonzero) digits is 6, while the sum is 8.
The square root of 130001120 is about 11401.8033661347. The cubic root of 130001120 is about 506.5811566989.
Adding to 130001120 its reverse (21100031), we get a palindrome (151101151).
It can be divided in two parts, 1300011 and 20, that added together give a palindrome (1300031).
The spelling of 130001120 in words is "one hundred thirty million, one thousand, one hundred twenty".
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