130001213149 has 2 divisors, whose sum is σ = 130001213150. Its totient is φ = 130001213148.

The previous prime is 130001213141. The next prime is 130001213159. The reversal of 130001213149 is 941312100031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 102704225625 + 27296987524 = 320475^2 + 165218^2 .

It is a cyclic number.

It is not a de Polignac number, because 130001213149 - 2³ = 130001213141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130001213141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65000606574 + 65000606575.

It is an arithmetic number, because the mean of its divisors is an integer number (65000606575).

Almost surely, 2^130001213149 is an apocalyptic number.

It is an amenable number.

130001213149 is a deficient number, since it is larger than the sum of its proper divisors (1).

130001213149 is an equidigital number, since it uses as much as digits as its factorization.

130001213149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 25.

The spelling of 130001213149 in words is "one hundred thirty billion, one million, two hundred thirteen thousand, one hundred forty-nine".