Base | Representation |
---|---|
bin | 111100100010010111… |
… | …0010110011010111110 |
3 | 110102120001201212120202 |
4 | 1321010232112122332 |
5 | 4112221004120110 |
6 | 135415550243502 |
7 | 12251366636441 |
oct | 1710456263276 |
9 | 412501655522 |
10 | 130002020030 |
11 | 50151829883 |
12 | 212414b6592 |
13 | c34a43110c |
14 | 6413873658 |
15 | 35ad1120a5 |
hex | 1e44b966be |
130002020030 has 32 divisors (see below), whose sum is σ = 235776605760. Its totient is φ = 51607468800.
The previous prime is 130002020023. The next prime is 130002020053. The reversal of 130002020030 is 30020200031.
130002020030 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a super-3 number, since 3×1300020200303 (a number of 34 digits) contains 333 as substring.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 130002019993 and 130002020020.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1573922 + ... + 1654458.
It is an arithmetic number, because the mean of its divisors is an integer number (7368018930).
Almost surely, 2130002020030 is an apocalyptic number.
130002020030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
130002020030 is a deficient number, since it is larger than the sum of its proper divisors (105774585730).
130002020030 is a wasteful number, since it uses less digits than its factorization.
130002020030 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 81764.
The product of its (nonzero) digits is 36, while the sum is 11.
Adding to 130002020030 its reverse (30020200031), we get a palindrome (160022220061).
The spelling of 130002020030 in words is "one hundred thirty billion, two million, twenty thousand, thirty".
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