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13000212204100 = 225211831131319619
BaseRepresentation
bin1011110100101101100100…
…0001111100101001000100
31201000210211010210121120121
42331023121001330221010
53200443413311012400
643352114240511324
72511143243325262
oct275133101745104
951023733717517
1013000212204100
1141623a4968890
12155b64091b544
13733bb7926584
1432d2dc2a3432
1517827310221a
hexbd2d907ca44

13000212204100 has 288 divisors, whose sum is σ = 31664608335360. Its totient is φ = 4593249024000.

The previous prime is 13000212204097. The next prime is 13000212204113. The reversal of 13000212204100 is 140221200031.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 1351509091 + ... + 1351518709.

It is an arithmetic number, because the mean of its divisors is an integer number (109946556720).

Almost surely, 213000212204100 is an apocalyptic number.

13000212204100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13000212204100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15832304167680).

13000212204100 is an abundant number, since it is smaller than the sum of its proper divisors (18664396131260).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13000212204100 is a wasteful number, since it uses less digits than its factorization.

13000212204100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9971 (or 9964 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 13000212204100 its reverse (140221200031), we get a palindrome (13140433404131).

The spelling of 13000212204100 in words is "thirteen trillion, two hundred twelve million, two hundred four thousand, one hundred".