130002201101 has 2 divisors, whose sum is σ = 130002201102. Its totient is φ = 130002201100.

The previous prime is 130002201041. The next prime is 130002201103. The reversal of 130002201101 is 101102200031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 92006055625 + 37996145476 = 303325^2 + 194926^2 .

It is a cyclic number.

It is not a de Polignac number, because 130002201101 - 2¹⁰ = 130002200077 is a prime.

It is a super-2 number, since 2×130002201101² (a number of 23 digits) contains 22 as substring.

Together with 130002201103, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130002201103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65001100550 + 65001100551.

It is an arithmetic number, because the mean of its divisors is an integer number (65001100551).

Almost surely, 2^130002201101 is an apocalyptic number.

It is an amenable number.

130002201101 is a deficient number, since it is larger than the sum of its proper divisors (1).

130002201101 is an equidigital number, since it uses as much as digits as its factorization.

130002201101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 130002201101 its reverse (101102200031), we get a palindrome (231104401132).

The spelling of 130002201101 in words is "one hundred thirty billion, two million, two hundred one thousand, one hundred one".