130003100 has 18 divisors (see below), whose sum is σ = 282106944. Its totient is φ = 52001200.

The previous prime is 130003091. The next prime is 130003103. The reversal of 130003100 is 1300031.

It is a super-2 number, since 2×130003100² = 33801612019220000, which contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130003103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 649916 + ... + 650115.

It is an arithmetic number, because the mean of its divisors is an integer number (15672608).

Almost surely, 2^130003100 is an apocalyptic number.

130003100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

130003100 is an abundant number, since it is smaller than the sum of its proper divisors (152103844).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130003100 is a wasteful number, since it uses less digits than its factorization.

130003100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1300045 (or 1300038 counting only the distinct ones).

The product of its (nonzero) digits is 9, while the sum is 8.

The square root of 130003100 is about 11401.8901941739. The cubic root of 130003100 is about 506.5837285373.

Adding to 130003100 its reverse (1300031), we get a palindrome (131303131).

Multiplying 130003100 by its reverse (1300031), we get a square (169008060096100 = 13000310²).

130003100 divided by its reverse (1300031) gives a square (100 = 10²).

The spelling of 130003100 in words is "one hundred thirty million, three thousand, one hundred".