Base | Representation |
---|---|
bin | 1011110100101110000000… |
… | …0111000111100110001000 |
3 | 1201000211010102100002012011 |
4 | 2331023200013013212020 |
5 | 3200444134214001300 |
6 | 43352134123025304 |
7 | 2511146215143505 |
oct | 275134007074610 |
9 | 51024112302164 |
10 | 13000331000200 |
11 | 4162455a28085 |
12 | 155b67466b234 |
13 | 733c0641b51b |
14 | 32d30dd884ac |
15 | 17827d76aeba |
hex | bd2e01c7988 |
13000331000200 has 24 divisors (see below), whose sum is σ = 30225769575930. Its totient is φ = 5200132400000.
The previous prime is 13000331000183. The next prime is 13000331000243. The reversal of 13000331000200 is 200013300031.
It can be written as a sum of positive squares in 3 ways, for example, as 11517620512644 + 1482710487556 = 3393762^2 + 1217666^2 .
It is a super-2 number, since 2×130003310002002 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 32500827301 + ... + 32500827700.
Almost surely, 213000331000200 is an apocalyptic number.
13000331000200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13000331000200 is an abundant number, since it is smaller than the sum of its proper divisors (17225438575730).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13000331000200 is a wasteful number, since it uses less digits than its factorization.
13000331000200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65001655017 (or 65001655008 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 13.
Adding to 13000331000200 its reverse (200013300031), we get a palindrome (13200344300231).
The spelling of 13000331000200 in words is "thirteen trillion, three hundred thirty-one million, two hundred", and thus it is an aban number.
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