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130010010239 is a prime number
BaseRepresentation
bin111100100010100110…
…0110101001001111111
3110102120121202211002102
41321011030311021333
54112230030311424
6135420433415315
712251524565504
oct1710514651177
9412517684072
10130010010239
1150156296a5a
122124410a53b
13c34bc9ac55
1464149534ab
1535adb8e7ae
hex1e4533527f

130010010239 has 2 divisors, whose sum is σ = 130010010240. Its totient is φ = 130010010238.

The previous prime is 130010010211. The next prime is 130010010241. The reversal of 130010010239 is 932010010031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130010010239 - 224 = 129993233023 is a prime.

Together with 130010010241, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 130010010239.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130010010259) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65005005119 + 65005005120.

It is an arithmetic number, because the mean of its divisors is an integer number (65005005120).

Almost surely, 2130010010239 is an apocalyptic number.

130010010239 is a deficient number, since it is larger than the sum of its proper divisors (1).

130010010239 is an equidigital number, since it uses as much as digits as its factorization.

130010010239 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 20.

The spelling of 130010010239 in words is "one hundred thirty billion, ten million, ten thousand, two hundred thirty-nine".