1300100103320 has 32 divisors (see below), whose sum is σ = 2930632351920. Its totient is φ = 519078775680.

The previous prime is 1300100103299. The next prime is 1300100103383. The reversal of 1300100103320 is 233010010031.

It is a junction number, because it is equal to n+sod(n) for n = 1300100103295 and 1300100103304.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 30017642 + ... + 30060921.

Almost surely, 2^{1300100103320} is an apocalyptic number.

1300100103320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1300100103320 is an abundant number, since it is smaller than the sum of its proper divisors (1630532248600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1300100103320 is a wasteful number, since it uses less digits than its factorization.

1300100103320 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 60079115 (or 60079111 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 1300100103320 its reverse (233010010031), we get a palindrome (1533110113351).

The spelling of 1300100103320 in words is "one trillion, three hundred billion, one hundred million, one hundred three thousand, three hundred twenty".