13001001211897 has 2 divisors, whose sum is σ = 13001001211898. Its totient is φ = 13001001211896.

The previous prime is 13001001211889. The next prime is 13001001211931. The reversal of 13001001211897 is 79811210010031.

It is an a-pointer prime, because the next prime (13001001211931) can be obtained adding 13001001211897 to its sum of digits (34).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11278722941161 + 1722278270736 = 3358381^2 + 1312356^2 .

It is a cyclic number.

It is not a de Polignac number, because 13001001211897 - 2³ = 13001001211889 is a prime.

It is not a weakly prime, because it can be changed into another prime (13001001211997) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500500605948 + 6500500605949.

It is an arithmetic number, because the mean of its divisors is an integer number (6500500605949).

Almost surely, 2^{13001001211897} is an apocalyptic number.

It is an amenable number.

13001001211897 is a deficient number, since it is larger than the sum of its proper divisors (1).

13001001211897 is an equidigital number, since it uses as much as digits as its factorization.

13001001211897 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3024, while the sum is 34.

The spelling of 13001001211897 in words is "thirteen trillion, one billion, one million, two hundred eleven thousand, eight hundred ninety-seven".