Base | Representation |
---|---|
bin | 1011110100110000100000… |
… | …0011110001100011111010 |
3 | 1201000212212010110101011010 |
4 | 2331030020003301203322 |
5 | 3201002022302242104 |
6 | 43352324424014350 |
7 | 2511201633641304 |
oct | 275141003614372 |
9 | 51025763411133 |
10 | 13001001212154 |
11 | 416276a28125a |
12 | 155b8210013b6 |
13 | 733cb222b247 |
14 | 32d374daa974 |
15 | 1782bc507489 |
hex | bd3080f18fa |
13001001212154 has 32 divisors (see below), whose sum is σ = 26898826965120. Its totient is φ = 4184198578112.
The previous prime is 13001001212153. The next prime is 13001001212219. The reversal of 13001001212154 is 45121210010031.
It is a self number, because there is not a number n which added to its sum of digits gives 13001001212154.
It is not an unprimeable number, because it can be changed into a prime (13001001212153) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 36307372 + ... + 36663704.
It is an arithmetic number, because the mean of its divisors is an integer number (840588342660).
Almost surely, 213001001212154 is an apocalyptic number.
13001001212154 is an abundant number, since it is smaller than the sum of its proper divisors (13897825752966).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13001001212154 is a wasteful number, since it uses less digits than its factorization.
13001001212154 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 566054.
The product of its (nonzero) digits is 240, while the sum is 21.
Adding to 13001001212154 its reverse (45121210010031), we get a palindrome (58122211222185).
The spelling of 13001001212154 in words is "thirteen trillion, one billion, one million, two hundred twelve thousand, one hundred fifty-four".
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