Base | Representation |
---|---|
bin | 1011110100110000100000… |
… | …0100000111100100011100 |
3 | 1201000212212010121221210212 |
4 | 2331030020010013210130 |
5 | 3201002022313133200 |
6 | 43352324425551552 |
7 | 2511201634465154 |
oct | 275141004074434 |
9 | 51025763557725 |
10 | 13001001302300 |
11 | 416276a332a60 |
12 | 155b8210455b8 |
13 | 733cb226029b |
14 | 32d374dd1764 |
15 | 1782bc524035 |
hex | bd30810791c |
13001001302300 has 36 divisors (see below), whose sum is σ = 30776915812776. Its totient is φ = 4727636836800.
The previous prime is 13001001302293. The next prime is 13001001302327. The reversal of 13001001302300 is 320310010031.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5909544947 + ... + 5909547146.
Almost surely, 213001001302300 is an apocalyptic number.
13001001302300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13001001302300 is an abundant number, since it is smaller than the sum of its proper divisors (17775914510476).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13001001302300 is a wasteful number, since it uses less digits than its factorization.
13001001302300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11819092118 (or 11819092111 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 13001001302300 its reverse (320310010031), we get a palindrome (13321311312331).
The spelling of 13001001302300 in words is "thirteen trillion, one billion, one million, three hundred two thousand, three hundred".
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