1300100312 has 64 divisors (see below), whose sum is σ = 2855139840. Its totient is φ = 543513600.

The previous prime is 1300100309. The next prime is 1300100317. The reversal of 1300100312 is 2130010031.

It is a junction number, because it is equal to n+sod(n) for n = 1300100293 and 1300100302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300100317) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 383987 + ... + 387357.

It is an arithmetic number, because the mean of its divisors is an integer number (44611560).

Almost surely, 2^1300100312 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1300100312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1427569920).

1300100312 is an abundant number, since it is smaller than the sum of its proper divisors (1555039528).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1300100312 is a wasteful number, since it uses less digits than its factorization.

1300100312 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3552 (or 3548 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 11.

The square root of 1300100312 is about 36056.9038049581. The cubic root of 1300100312 is about 1091.4209540834.

Adding to 1300100312 its reverse (2130010031), we get a palindrome (3430110343).

It can be divided in two parts, 130010031 and 2, that multiplied together give a palindrome (260020062).

The spelling of 1300100312 in words is "one billion, three hundred million, one hundred thousand, three hundred twelve".