130010100100122 has 64 divisors (see below), whose sum is σ = 300349223164800. Its totient is φ = 37078907873280.

The previous prime is 130010100100103. The next prime is 130010100100123. The reversal of 130010100100122 is 221001001010031.

It is a super-2 number, since 2×130010100100122² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130010100100098 and 130010100100107.

It is not an unprimeable number, because it can be changed into a prime (130010100100123) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 68184904 + ... + 70065692.

It is an arithmetic number, because the mean of its divisors is an integer number (4692956611950).

Almost surely, 2^{130010100100122} is an apocalyptic number.

130010100100122 is an abundant number, since it is smaller than the sum of its proper divisors (170339123064678).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130010100100122 is a wasteful number, since it uses less digits than its factorization.

130010100100122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1942431.

The product of its (nonzero) digits is 12, while the sum is 12.

Adding to 130010100100122 its reverse (221001001010031), we get a palindrome (351011101110153).

Subtracting 130010100100122 from its reverse (221001001010031), we obtain a palindrome (90990900909909).

The spelling of 130010100100122 in words is "one hundred thirty trillion, ten billion, one hundred million, one hundred thousand, one hundred twenty-two".