Base | Representation |
---|---|
bin | 11000001101110101… |
… | …11011110001111001 |
3 | 1020120001200221221121 |
4 | 30012322323301321 |
5 | 203111224430033 |
6 | 5550024505241 |
7 | 640114541023 |
oct | 140672736171 |
9 | 36501627847 |
10 | 13001014393 |
11 | 55718085a4 |
12 | 262a01b221 |
13 | 12c2668633 |
14 | 8b4951013 |
15 | 5115a262d |
hex | 306ebbc79 |
13001014393 has 2 divisors, whose sum is σ = 13001014394. Its totient is φ = 13001014392.
The previous prime is 13001014373. The next prime is 13001014421. The reversal of 13001014393 is 39341010031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9071229049 + 3929785344 = 95243^2 + 62688^2 .
It is a cyclic number.
It is not a de Polignac number, because 13001014393 - 25 = 13001014361 is a prime.
It is not a weakly prime, because it can be changed into another prime (13001014373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500507196 + 6500507197.
It is an arithmetic number, because the mean of its divisors is an integer number (6500507197).
Almost surely, 213001014393 is an apocalyptic number.
It is an amenable number.
13001014393 is a deficient number, since it is larger than the sum of its proper divisors (1).
13001014393 is an equidigital number, since it uses as much as digits as its factorization.
13001014393 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 25.
The spelling of 13001014393 in words is "thirteen billion, one million, fourteen thousand, three hundred ninety-three".
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