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130010203110 = 2354333673437
BaseRepresentation
bin111100100010100110…
…1100100001111100110
3110102120122010121122210
41321011031210033212
54112230102444420
6135420441504250
712251526331014
oct1710515441746
9412518117583
10130010203110
1150156408957
12212441a2086
13c34c037988
1464149a38b4
1535adbcb9e0
hex1e453643e6

130010203110 has 16 divisors (see below), whose sum is σ = 312024487536. Its totient is φ = 34669387488.

The previous prime is 130010203069. The next prime is 130010203129. The reversal of 130010203110 is 11302010031.

It is a super-3 number, since 3×1300102031103 (a number of 34 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2166836689 + ... + 2166836748.

It is an arithmetic number, because the mean of its divisors is an integer number (19501530471).

Almost surely, 2130010203110 is an apocalyptic number.

130010203110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

130010203110 is an abundant number, since it is smaller than the sum of its proper divisors (182014284426).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130010203110 is a wasteful number, since it uses less digits than its factorization.

130010203110 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4333673447.

The product of its (nonzero) digits is 18, while the sum is 12.

Adding to 130010203110 its reverse (11302010031), we get a palindrome (141312213141).

The spelling of 130010203110 in words is "one hundred thirty billion, ten million, two hundred three thousand, one hundred ten".

Divisors: 1 2 3 5 6 10 15 30 4333673437 8667346874 13001020311 21668367185 26002040622 43336734370 65005101555 130010203110