Base | Representation |
---|---|
bin | 10010111010110100001… |
… | …000101110110001110111 |
3 | 11121021210100212101120121 |
4 | 102322310020232301313 |
5 | 132300102142423111 |
6 | 2433131520312411 |
7 | 162633514210306 |
oct | 22726410566167 |
9 | 4537710771517 |
10 | 1300102311031 |
11 | 461408951a67 |
12 | 18bb75772707 |
13 | 957a3369b04 |
14 | 46cd4dbc43d |
15 | 23c42dd4871 |
hex | 12eb422ec77 |
1300102311031 has 2 divisors, whose sum is σ = 1300102311032. Its totient is φ = 1300102311030.
The previous prime is 1300102311029. The next prime is 1300102311043. The reversal of 1300102311031 is 1301132010031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1300102311031 - 21 = 1300102311029 is a prime.
It is a super-2 number, since 2×13001023110312 (a number of 25 digits) contains 22 as substring.
Together with 1300102311029, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 1300102310996 and 1300102311014.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1300102311071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650051155515 + 650051155516.
It is an arithmetic number, because the mean of its divisors is an integer number (650051155516).
Almost surely, 21300102311031 is an apocalyptic number.
1300102311031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1300102311031 is an equidigital number, since it uses as much as digits as its factorization.
1300102311031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 1300102311031 its reverse (1301132010031), we get a palindrome (2601234321062).
The spelling of 1300102311031 in words is "one trillion, three hundred billion, one hundred two million, three hundred eleven thousand, thirty-one".
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