13001031122111 has 2 divisors, whose sum is σ = 13001031122112. Its totient is φ = 13001031122110.

The previous prime is 13001031122099. The next prime is 13001031122113. The reversal of 13001031122111 is 11122113010031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13001031122111 - 2⁴² = 8602984611007 is a prime.

Together with 13001031122113, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13001031122111.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13001031122113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500515561055 + 6500515561056.

It is an arithmetic number, because the mean of its divisors is an integer number (6500515561056).

Almost surely, 2^{13001031122111} is an apocalyptic number.

13001031122111 is a deficient number, since it is larger than the sum of its proper divisors (1).

13001031122111 is an equidigital number, since it uses as much as digits as its factorization.

13001031122111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 13001031122111 its reverse (11122113010031), we get a palindrome (24123144132142).

The spelling of 13001031122111 in words is "thirteen trillion, one billion, thirty-one million, one hundred twenty-two thousand, one hundred eleven".