Base | Representation |
---|---|
bin | 11000001101110110… |
… | …00000100100011100 |
3 | 1020120001201221212020 |
4 | 30012323000210130 |
5 | 203111231042022 |
6 | 5550025140140 |
7 | 640114652151 |
oct | 140673004434 |
9 | 36501657766 |
10 | 13001034012 |
11 | 557182130a |
12 | 262a02a650 |
13 | 12c2674545 |
14 | 8b4958228 |
15 | 5115a835c |
hex | 306ec091c |
13001034012 has 48 divisors (see below), whose sum is σ = 32317138560. Its totient is φ = 4056118848.
The previous prime is 13001033963. The next prime is 13001034043. The reversal of 13001034012 is 21043010031.
It is a super-2 number, since 2×130010340122 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13001033982 and 13001034000.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 324583 + ... + 362430.
It is an arithmetic number, because the mean of its divisors is an integer number (673273720).
Almost surely, 213001034012 is an apocalyptic number.
13001034012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
13001034012 is an abundant number, since it is smaller than the sum of its proper divisors (19316104548).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13001034012 is a wasteful number, since it uses less digits than its factorization.
13001034012 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 687122 (or 687120 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 13001034012 its reverse (21043010031), we get a palindrome (34044044043).
The spelling of 13001034012 in words is "thirteen billion, one million, thirty-four thousand, twelve".
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