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1300105301317 is a prime number
BaseRepresentation
bin10010111010110100010…
…100001000110101000101
311121021210120111022110221
4102322310110020311011
5132300103424120232
62433132104344341
7162633551503324
oct22726424106505
94537716438427
101300105301317
1146140a604679
1218bb767750b1
13957a3b75c04
1446cd555a0bb
1523c432c5897
hex12eb4508d45

1300105301317 has 2 divisors, whose sum is σ = 1300105301318. Its totient is φ = 1300105301316.

The previous prime is 1300105301197. The next prime is 1300105301357. The reversal of 1300105301317 is 7131035010031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 745138409796 + 554966891521 = 863214^2 + 744961^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1300105301317 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1300105301291 and 1300105301300.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1300105301357) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650052650658 + 650052650659.

It is an arithmetic number, because the mean of its divisors is an integer number (650052650659).

Almost surely, 21300105301317 is an apocalyptic number.

It is an amenable number.

1300105301317 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300105301317 is an equidigital number, since it uses as much as digits as its factorization.

1300105301317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 945, while the sum is 25.

The spelling of 1300105301317 in words is "one trillion, three hundred billion, one hundred five million, three hundred one thousand, three hundred seventeen".