130011103 has 2 divisors, whose sum is σ = 130011104. Its totient is φ = 130011102.

The previous prime is 130011073. The next prime is 130011107. The reversal of 130011103 is 301110031.

It is a strong prime.

It is an emirp because it is prime and its reverse (301110031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-130011103 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 130011103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130011107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65005551 + 65005552.

It is an arithmetic number, because the mean of its divisors is an integer number (65005552).

Almost surely, 2^130011103 is an apocalyptic number.

130011103 is a deficient number, since it is larger than the sum of its proper divisors (1).

130011103 is an equidigital number, since it uses as much as digits as its factorization.

130011103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9, while the sum is 10.

The square root of 130011103 is about 11402.2411393550. The cubic root of 130011103 is about 506.5941234340.

Adding to 130011103 its reverse (301110031), we get a palindrome (431121134).

It can be divided in two parts, 1300 and 11103, that added together give a triangular number (12403 = T₁₅₇).

The spelling of 130011103 in words is "one hundred thirty million, eleven thousand, one hundred three".