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13001120983 is a prime number
BaseRepresentation
bin11000001101110110…
…10101110011010111
31020120001220101011101
430012323111303113
5203111241332413
65550031050531
7640115463544
oct140673256327
936501811141
1013001120983
115571880694
12262a070a47
1312c26a4cc6
148b497bbcb
155115c3edd
hex306ed5cd7

13001120983 has 2 divisors, whose sum is σ = 13001120984. Its totient is φ = 13001120982.

The previous prime is 13001120981. The next prime is 13001120999. The reversal of 13001120983 is 38902110031.

It is a weak prime.

It is an emirp because it is prime and its reverse (38902110031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13001120983 - 21 = 13001120981 is a prime.

Together with 13001120981, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13001120981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500560491 + 6500560492.

It is an arithmetic number, because the mean of its divisors is an integer number (6500560492).

Almost surely, 213001120983 is an apocalyptic number.

13001120983 is a deficient number, since it is larger than the sum of its proper divisors (1).

13001120983 is an equidigital number, since it uses as much as digits as its factorization.

13001120983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 28.

The spelling of 13001120983 in words is "thirteen billion, one million, one hundred twenty thousand, nine hundred eighty-three".